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How to determine if build is running in GUI or console app
Use the Application object's Context property.
http://www.kinook.com/VisBuildPro/Ma...xtproperty.htm For instance, within a VBScript Run Script step: Code:
If Application.Context = vbldContextGUI Then Builder.LogMessage "Running in GUI" ElseIf Application.Context = vbldContextCommandLine Then Builder.LogMessage "Running in console" Else Builder.LogMessage "Running via object model" End If |
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